we have
[tex]f(x)=4x+8[/tex]
Step 1
Let
[tex]y=f(x)[/tex]
[tex]y=4x+8[/tex]
Step 2
exchanges the variable x for y and the variable y for x
[tex]x=4y+8[/tex]
Step 3
Isolate the variable y
[tex]4y=x-8[/tex]
[tex]y=\frac{1}{4}x-2[/tex]
Step 4
Let
[tex]h^{-1}(x)=y[/tex]
[tex]h^{-1}(x)=\frac{1}{4}x-2[/tex] ------> the inverse function
therefore
the answer is
[tex]h^{-1}(x)=\frac{1}{4}x-2[/tex]