If the initial velocity of an object was -2 meters per second
and the final velocity was -10 meters per second
and this change in velocity took16 seconds...
What was the acceleration?
(Note: Round to 2 decimal places)
m/s
A :-) for this question , we should apply a = v - u by t Given - u = -2 m/s v = -10 m/s t = 16 sec Solution - a = v - u by t a = -10 - -2 by 16 a = -12 by 16 ( cut 12 and 16 because 2 x 6 = 12 and 2 x 8 = 16 ) ( cut 6 and 8 because 2 x 3 = 6 and 2 x 4 = 8 ) a = 3 by 4 a = 0.75 m/s^2
