Line II 2x+3y=-5 3y=-2x-5 y=[tex] \frac{-2}{3} x- \frac{5}{3} [/tex]
Gradient m= [tex] \frac{-2}{3} [/tex] Gradient of line I will be; [tex] \frac{-2}{3} *m=-1[/tex] m=[tex] \frac{3}{2} [/tex] Equation of line I; y=mx+c y=[tex] \frac{3}{2} x+c[/tex] Finding value of c by replacing for; y=1 x=-6 1=[tex] \frac{3}{2} *(-6)+c[/tex] c=10 y=[tex] \frac{3}{2} x+10[/tex]
